non-differentiability of the square-root terms (and l1 norms) (see Xu et al., ICML 2013)
Given any g(x) > 0, the following holds:
\sqrt(g(x)) = \min_{z>0} \frac{1}{2}[\frac{g(x)}{z}+z].
Then add this auxiliary variable to your cost.
Monday, November 4, 2013
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